solved: For π‘Ž ο»Ώis a real number and | π‘Ž | < 1 , ο»Ώshow that ∫ 0 2 πœ‹ 1 - π‘Ž 𝑐 π‘œ 𝑠 πœƒ 1 - 2 π‘Ž 𝑐 π‘œ 𝑠 πœƒ + π‘Ž 2 𝑑 πœƒ = 2 πœ‹ .

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ForΒ π‘ŽΒ is a real number andΒ |π‘Ž|<1,Β show that ∫02πœ‹1-π‘Žπ‘π‘œπ‘ πœƒ1-2π‘Žπ‘π‘œπ‘ πœƒ+π‘Ž2π‘‘πœƒ=2πœ‹.

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